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[ Chemistry ] Open Question : CHEMISTRY Kp and Keq from Mole Fractions and PV=nRT?
At 787�C and 1.00 atm pressure, a gaseous mixture of carbon monoxide and carbon dioxide is in equilibrium with solid carbon according to the reaction equation
C(s) + CO2(g) == 2CO(g)
If the gaseous mixture is 78.67% CO by mass, what is the equilibrium constant (Kp expressed in terms of the partial pressures in atm) at this temperature?
i found out the partial pressures but now im stuck help please
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[ Chemistry ] Open Question : CHEMISTRY Kp and Keq from Mole Fractions and PV=nRT?
At 787�C and 1.00 atm pressure, a gaseous mixture of carbon monoxide and carbon dioxide is in equilibrium with solid carbon according to the reaction equation
C(s) + CO2(g) == 2CO(g)
If the gaseous mixture is 78.67% CO by mass, what is the equilibrium constant (Kp expressed in terms of the partial pressures in atm) at this temperature?
i found out the partial pressures but now im stuck help please
Visit Hotels Ohio Cleveland to read more information on Hotels Ohio Cleveland.
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